Baco3 H2o

Baco3 H2o

Directions.Perform the indicated calculations to find the molar mass of the following compounds.Item no.1 serves as an example 1.BaCO32.H2O3.Ag2SO4.NH4CI5.NaOH6.KMnO47.MfCl28.Be(NO3)2​

Daftar Isi

1. Directions.Perform the indicated calculations to find the molar mass of the following compounds.Item no.1 serves as an example 1.BaCO32.H2O3.Ag2SO4.NH4CI5.NaOH6.KMnO47.MfCl28.Be(NO3)2​


Molar Mass

Answer:

1.) BaCO3

    Ba : 1 x 137.328 g/mol = 137.328 g/mol

    C   : 1 x 12.011 g/mol = 12.011 g/mol

    O   : 3 x 15.999 g/mol = 47.997 g/mol

                                            197.336 g/mol

   Molar Mass of BaCO3 = 197.336 g/mol

2.) H2O

    H : 2 x 1.008 g/mol = 2.016 g/mol

    O : 1 x 15.999 g/mol = 15.999 g/mol

                                         18. 015 g/mol

   

    Molar mass of H2O = 18.015 g/mol

3.) Ag2SO

    Ag : 2 x 107.868 g/mol = 215.736 g/mol

    S   : 1 x 32.066 g/mol = 32. 066 g/mol

    O  : 1 x 15.999 g/mol = 15.999 g/mol

                                           263. 801 g/mol

  Molar Mass of Ag2SO = 263.801 g/mol

4.) NH4Cl

    N : 1 x 14.007 g/mol = 14.007 g/mol

    H : 4 x 1.008 g/mol = 4.032 g/mol

    Cl : 1 x 35.453 g/mol = 35.453 g/mol

                                           53.492 g/mol

     Molar Mass of NH4Cl = 53.492 g/mol

5.) NaOH

    Na : 1 x 22.990 g/mol = 22.990 g/mol

    O   : 1 x 15.999 g/mol = 15.999 g/mol

    H   : 1 x 1.008 g/mol = 1.008 g/mol

                                         39.997 g/mol

    Molar Mass of NaOH = 39. 997 g/mol

6.) KMnO4

     K    : 1 x 39.098 g/mol = 39.098 g/mol

     Mn : 1 x 54.938 g/mol = 54.938 g/mol

     O    : 4 x 15.999 g/mol = 63.996 g/mol

                                               158.032 g/mol

     Molar Mass of KMnO4 = 158.032 g/mol

7.) MgCl2

    Mg : 1 x 24.305 g/mol = 24.305 g/mol

    Cl   : 2 x 35.453 g/mol = 70.906 g/mol

                                              95.211 g/mol

  Molar Mass of MgCl2 = 95.211 g/mol

8.) Be (NO3)2

    Be : 1 x 9.012 g/mol = 9.012 g/mol

    N   : 2 x 14.007 g/mol = 28. 014 g/mol

    O   : 6 x 15.999 g/mol = 95.994 g/mol

                                            133. 02 g/mol

    Molar Mass of Be (NO3)2 = 133.02 g/mol

Explanation:

Compounds are substances that are made up of more than one element. To find the molar mass, we follow the steps below:

1. Find the atomic masses of individual elements in the periodic table. These atomic masses can be found in the periodic table of elements.

Example: BaCO3 - the molar masses of the elements are:

               Ba is 137.328 g/mol, C is 12.011 g/mol, and O is 15.999 g/mol.

   

2. Count how many atoms there are for each element. This is written as subscripts of the compound.

    For Ba - 1, C - 1 and O - 3

3. Find the molar mass of each element by multiplying the molar mass of the element by the number of atoms present. Then, get the sum of the molar masses.

    Ba : 1 x 137.328 g/mol = 137.328 g/mol

    C   : 1 x 12.011 g/mol = 12.011 g/mol

    O   : 3 x 15.999 g/mol = 47.997 g/mol

                                            197.336 g/mol

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2. Is BaCO3 compound is organic or inorganic​


Answer:

Inorganic

Explanation:

It only has one Carbon. In order to for a compound to be organic, it should have a carbon chain or atleast 2 carbons.

Answer: Inorganic

Explanation: Barium carbonate is inorganic compound


3. how many formula units are there in 2.71 mole of BaCO3​


Answer:

532.8069300000001 grams


4. how many grams of h2o are present in 2.5 moles of h2o?​


Answer:

40 grams.

Explanation:

correct me if im wrong:>

Answer:

45.0 g

Explanation:

Molar mass of H2o is 18.0 g/mol

. Mass of 2.50 moles of H2o is

2.50

moles

×

18.0g

mol

=

45.0 g


5. 4. How many molecules of H2O are in one mole H2O of molecules? *A. 3.01 x 10^23 H2O of moleculesB. 6.02 x 10^23 H2O of moleculesC. 3.34 x 10^24 H2O of moleculesD. 6.02 x 10^24 H O of molecules​


Answer:

In one mole are 6.02×10^23 H2O molecules.

Explanation:

hopes it helps you a lot ..pabrainliwst na din


6. 27. What is the empirical formula of a compound that is composed of 69.58 % Barium, 6.090% Carbon, and 24.32 % Oxygen? *A. BaC2O4B. BaCO4C. BaCO2D. BaCO3​


Solution:

Step 1: Assume that the mass of a compound is 100 g.

[tex]\text{mass Ba = 69.58 g}[/tex]

[tex]\text{mass C = 6.090 g}[/tex]

[tex]\text{mass O = 24.32 g}[/tex]

Step 2: Calculate the number of moles of each element.

[tex]n \: \text{Ba = 69.58 g} × \frac{\text{1 mol}}{\text{137.3 g}} = \text{0.5068 mol}[/tex]

[tex]n \: \text{C = 6.090 g} × \frac{\text{1 mol}}{\text{12.01 g}} = \text{0.5071 mol}[/tex]

[tex]n \: \text{O = 24.32 g} × \frac{\text{1 mol}}{\text{16.00 g}} = \text{1.520 mol}[/tex]

Step 3: Represent an empirical formula.

[tex]\text{empirical formula} = \text{Ba}_{x}\text{C}_{y}\text{O}_{z}[/tex]

Step 4: Divide the number of moles of each element by the least number of moles.

[tex]x = \frac{\text{0.5068 mol}}{\text{0.5068 mol}} = 1[/tex]

[tex]y = \frac{\text{0.5071 mol}}{\text{0.5068 mol}} = 1[/tex]

[tex]z = \frac{\text{1.520 mol}}{\text{0.5068 mol}} = 3[/tex]

Step 5: Write the empirical formula.

[tex]\boxed{\text{empirical formula} = \text{BaCO}_{3}}[/tex]

Answer:

D. BaCO₃

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7. A 0.1799g sample of an organic compound was burned in a stream of oxygen and the CO2 produced was collected in a solution of barium hydroxide. Calculate the percentage of carbon in the sample if 0.5613g of BaCO3 was formed


The percentage of carbon : = 18.95%

Further explanation  

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.  

Reaction

CO₂ + Ba(OH)₂ ⇒ BaCO₃ + H₂O

mol BaCO₃(MW=197,34 g/mol) :

= 0.5613 : 197.34

= 0.002844

From the equation, mol ratio of CO₂ : BaCO₃ = 1 : 1, so mol CO₂=0.002844

Mass CO₂ :

= mol x MW

= 0.002844 x 44 g/mol

= 0.125 g

Mass C in CO₂ :

= (12 : 44) x 0.125

= 0.03409

%C in the sample :

= (mass C : mass sample) x 100%

= (0.03409 g : 0.1799) x 100%

= 18.95%

Learn more  

the mass in grams of 3.5 mol of the element gold.  

https://brainly.ph/question/1373453  

the mass percent  

https://brainly.ph/question/242314  

https://brainly.ph/question/241424  

#LetsStudy  


8. how many moles of h2o are there in 36.2 grams of h2o?


Answer:

n H2O = 2.01 mol

Explanation:

n H2O = 36.2 g H2O × (1 mol H2O / 18.015 g H2O)

n H2O = 2.01 mol

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9. How many molecules of h2o are there in 0.75 mol of h2o


Answer:

4.52 × 10²³ molecules

Explanation:

nasa pic yung explanation


10. What happens to the temperature of H2O while changing from ice to liquid H2O.?


it will increase because matutunaw kasi young ice tapos maginging tubig ulit

11. how many molecules of h2o are there in 2 moles of h2o


Just like the dozen and the gross, it is a name that stands for a number. There are therefore 6.02 × 10 ²³ water molecules in a mole of water molecules.


12. Which statement about the critical point of h2o and supercritical h2o is true?


Answer:

H2O is the chemical formula of water. It means that each molecule of water is made up of two hydrogen atoms, indicated by the letter H, and a single oxygen atom, represented by the letter O. Water is chemical substance with no smell, taste or color.

Explanation:

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13. What is the most important compound in human body? A. H2O and NaCl B. H2O and NAOH C. NH3 and H2O D. HCl and H20


Answer:

D HCI AND H20

Explanation:

Wala feel ko lang


14. How many molecules of h2o are there in 0.75 mol of h2o


Answer:

- the molecules of h2o are there in 0.75 mol of h2o is

4.52 x 10²³


15. How many molecules of H2O are there in 0.75 mol of H2O?​


Explanation:

How many molecules are in 0.75 moles?

Part of a video titled Q21 What is the number of molecules in 0.75 moles of Nitrogen? - YouTube

0:32

0:59

Within 0.75 mole may I have a guide rows number multiplied by 0.75 J molecules only that is four point one four five and six five multiplied by 10 raised to the power 23. Molecules you.


16. A mixture of na2co3 and baco3 weighing 0.2000 g requires 30.0 ml of 0.1000n acid for complete neutralization. what is the percent of each component in the mixture


Answer:

Sodium carbonate reacts with hydrochloric acid:

N
a
2
C
O
3
(
s
)
+
2
H
C
l
(
a
q
)

2
N
a
C
l
(
a
q
)
+
C
O
2
(
g
)
+
H
2
O
(
l
)


We can find the number of moles of
HCl
before the reaction.

We then use the titration result to find the number of moles remaining after the reaction.

By subtracting the two we can get the number of moles of
HCl
which have reacted.

From the equation we can find the number of moles of
Na
2
CO
3
.

From this we get the mass of
Na
2
CO
3
.

We can then work out the percentage purity.

Concentration = moles of solute / volume of solution.

c
=
n
v



n
=
c
×
v



Initial moles of
H
C
l
=
0.1280
×
50.00
1000
=
6.400
×
10

3


The acid remaining is titrated with
NaOH
:

H
C
l
(
a
q
)
+
N
a
O
H
(
a
q
)

N
a
C
l
(
a
q
)
+
H
2
O
(
l
)


n
O
H

=
0.1220
×
30.10
1000
=
3.6722
×
10

3


Since they react in a 1:1 ratio the no. of moles of
HCl
must be the same:

n
H
C
l
=
3.6722
×
10

3



The no. moles used up:

=
(
6.400

3.6722
)
×
10

3
=
2.7228
×
10

3


From the original equation you can see that the no. moles of
Na
2
CO
3
must be half of this.


n
N
a
2
C
O
3
=
2.7228
×
10

3
2
=
1.3614
×
10

3


M
r
[
N
a
2
C
O
3
]
=
105.99




m
a
s
s

N
a
2
C
O
3
=
1.3614
×
10

3
×
105.99
=
0.14429

g




percentage purity

=
0.14429
0.3240
×
100
=
44.53
%


This technique is known as a "back titration".


17. Which of these is the correct equation for photosynthesis? a)O2 + C6H12O6 --> CO2 + H2O B)O2 + CO2 --> C6H12O6 + H2O c)CO2 + H2O --> O2 + C6H12O6 D)CO2 + H2O --> O2 + C6O12H6


Answer:

C. CO2+H2O > O2+C6H12O6

Explanation:

This means that the reactants, six carbon dioxide molecules and six water molecules, are converted by light energy captured by chlorophyll (implied by the arrow) into a sugar molecule and six oxygen molecules, the products.


18. How many molecules of H2O are there in 0.70 mol of H2O


Answer:

no. of H2O molecules = 4.2 × 10²³ molecules

Explanation:

no. of H2O molecules = 0.70 mol H2O × (6.022 × 10²³ H2O molecules / 1 mol H2O)

no. of H2O molecules = 4.2 × 10²³ molecules

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19. How many moles of water are present in 250g of ice?A. 13.9 mol H2OB. 14.9 mol H2OC. 15.9 mol H2OD. 16.9 mol H2O​


Answer:

Ice is water, in solid form

# mols H2O in 250 g H2O(s) = 250 g H2O(1 mol H2O/18 g H2O)

[n = 250 grams ÷ 19.0 g/mol] = 13.9 moles.

So therefore the answer is A.


20. 8. C3H8 + 02 → CO2 + H2O + 9. Fe + H2O → H2+ Fe3O4​


e calculator nyo po. thank you


21. how many molecules of h2o are there in 7.0 moles of h2o?​


Answer:

omsim barabida omsim barabida omsim


22. balancing equal equations H2O +H2O +O2


inlove ako kase mahal ko sya


23. balance the equations1.SnO2 + H2 → Sn + H2O2.Na + H2O → NaOH + H2O​


Answer:

1.) SnO2 + 2H2 → Sn + 2H2O

2.) 2Na + 2H2O → 2NaOH + H2

Explanation:

                 


24. which is the correct representation of the reaction a.CaO+H2O-----Ca+H30 b. CaO+H2O-----Ca(OH)2 c. 2Cao+H2O------Cao d.Ca(OH)2----CaO+H2O


Answer

B. CaO+H2O=Ca(OH)2.


25. determine the number of h2o molecules in 56.12 g of h2o


Answer:

h2o means water h2o hydrogen and oxygen


26. identify the possible intermolecular force attraction of H2O-----H2O​


Answer:

The H2O water molecule is polar with intermolecular dipole-dipole hydrogen bonds. As the water molecules attract each other and form bonds, water displays properties such as high surface tension and a high heat of vaporization.

HOPE IT HELPS ❤


27. How many molecules of h2o are there in 9.75 mol of h2o


Answer:

9.5 x 1023 / 6.02 x 1023 = 1.58 moles H2O.

Explanation:

Converting from number of molecules to moles is easy as long as you know that 1 mole = 6.02X1023 molecules. This is true for any substance. If we have 9.5 x 1023 water molecules, we divide that by 6.02 x 1023 to get the number of moles

Answer:

Converting from number of molecules to moles is easy as long as you know that 1 mole = 6.02X1023 molecules. This is true for any substance. If we have 9.5 x 1023 water molecules, we divide that by 6.02 x 1023 to get the number of moles: 9.5 x 1023 / 6.02 x 1023 = 1.58 moles H2O.

Explanation:

pa brainlest nalang po


28. Which of the following shows the balanced equation for the reaction that represents the decomposition of barium carbonate (baco3)?


QUESTION:

Which of the following shows the balanced equation for the reaction that represents the decomposition of barium carbonate (BaCO₃)?

ANSWER:

BaCO₃ → BaO + CO₂

[tex]\\[/tex]

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29. 1.53g NaCI100 gH202.27gNaci100g H2O3.16g NaCI100g H2O4.7g NaCI100g H2O5.18g NaCI100g H2O​


Answer:

anong oras magsisimula qng patimpalak


30. How many molecules are there in 1.5 moles of water? a. 9.03 x 1023 molecules H2O b. 9.03 x 1023 atoms H2O c. 0.90 x 1024 molecules H2O d. 90.3 x 1024 atoms H2O​


Answer:

A. 9.03 ...

Explanation:

Sana makatulong


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