Projectile Motion (sample problem)
1. Projectile Motion (sample problem)
Answer:
This example problem shows how to do all of these.
Projectile Motion Example Problem: A cannon is fired with muzzle velocity of 150 m/s at an angle of elevation = 45°. Gravity = 9.8 m/s2. ...
Part a) Find h.
Part b: Find total time aloft.
Part c: Find range R.
Part d: Find the position at t = 10 seconds.
Explanation:
Just copy it
2. which of the is not considered a projectile motion problem?
Answer:
Answer:An aircraft taking off. Explanation: When aircraft take off it doesn't follow a parabolic path. So, it is not a projectile motion.
Explanation:
pa brainless po thank you
3. give problem solving of projectile motion
Answer:
Problem: A soccer player kicks a ball from the ground with an initial velocity of 20 meters per second at an angle of 45 degrees to the horizontal. Calculate the maximum height the ball will reach, the time it takes to reach the highest point, and the horizontal distance it travels before hitting the ground.
Solution:
Step 1: Analyze the given information and set up the problem
Initial velocity (v0) = 20 m/s
Launch angle (θ) = 45 degrees
Gravity (g) = 9.81 m/s^2 (downward)
We can use the equations of motion for projectile motion to solve this problem:
y = y0 + v0y * t - 0.5 * g * t^2 (equation for vertical motion)
x = x0 + v0x * t (equation for horizontal motion)
v0x = v0 * cos(θ)
v0y = v0 * sin(θ)
Step 2: Calculate the maximum height the ball will reach
At the highest point of the trajectory, the vertical velocity of the ball will be zero. Using the equation for vertical motion and the fact that v = 0 at the highest point, we can find the time it takes to reach the highest point:
v = v0y - g * t
0 = v0y - g * t
t = v0y / g
Substituting this value of t into the equation for vertical motion, we can find the maximum height (y):
y = y0 + v0y * t - 0.5 * g * t^2
y = 0 + (20 * sin(45)) * (20 * sin(45) / g) - 0.5 * g * (20 * sin(45) / g)^2
y = 20.20 meters
Therefore, the maximum height the ball will reach is 20.20 meters.
Step 3: Calculate the time it takes to reach the highest point
We already calculated this in Step 2. The time it takes to reach the highest point is t = v0y / g = (20 * sin(45)) / 9.81 = 1.45 seconds.
Step 4: Calculate the horizontal distance it travels before hitting the ground
Using the equation for horizontal motion, we can find the distance (x) the ball travels before hitting the ground:
x = x0 + v0x * t
x = 0 + (20 * cos(45)) * (2 * 1.45)
x = 41.01 meters
Therefore, the horizontal distance the ball travels before hitting the ground is 41.01 meters.
Answer:
Maximum height reached = 20.20 meters
Time to reach highest point = 1.45 seconds
Horizontal distance traveled = 41.01 meters
Explanation:
I just found this on the internet since you didn't really give exact details on the solving part.
4. research about 2 types of projectile motion horizontal and vertical motions of projectile
Answer:
a projectile is an object up on which the only force acting is gravity there are a variety of the examples of projectile dropped from rest is a projectile provide that influence of air resistance and negligible an object that is thrown vertically upward is also projectile provided that the influence of air resistance is labeling project the motion can happen into situation projectiles launched rosanta land projectile launched an angle
5. a flight of soccer ball projectile motion or non projectile motion
Answer:
When the soccer ball is kicked into the air it becomes a projectile and follows a parabolic path through the air. This is how soccer players get the ball up and over defenders with free kicks and across the field with crosses.
6. projectile motion is the motion of a projectile with a constant acceleration a.true b.false
Answer:
a true
Explanation:
7. Refers to the path traced by a projectile it's motion.A. TrajectoryB. ParabolaC. Projectile motionD. Force and motion
Answer:
C. Projectile motion
Explanation:
Projectile motion is a form of motion where an object moves in parabolic path; the path that the object follows is called its trajectory.
8. 100 m dish projectile motion or non projectile motion
Answer:projectile motion
9. Create a problem about projectile motion and provide a solution
Answer:
I am working on a project which involves launching a tennis ball at a certain velocity and angle in order to hit a given target. To do so, I have just started diving into projectile motion and am thus a beginner in this field. However, manipulating the basic equations to get results is pretty straight forward in most cases.
My problem: I have implemented a solver that calculates the needed launch angle for given initial projectile velocity, position of launcher and position of target in order to reach the target.
where y is the height of the target, y0 is the height of the launcher, Δy=y−y0, and similarly for x, x0, and Δx. θ, v0, and g are, respectively, the launch angle, the initial velocity and gravitational acceleration.
Given that the unknown X that we are solving for is defined as X=tan(θ), the roots can be expressed as
v20±v40−g(gΔ2x+2Δyv20)−−−−−−−−−−−−−−−−−√gΔx
Now here is the tricky part: when I input the values of a similar problem I found on the internet (Δx=600 m, Δy=40 m, v0=100 m/s), I find the exact same angles as the solutions stated in this problem. However, when I input random values, I almost always get imaginary solutions. For example Δx=30 m, Δy=0 m, v0=10 m/s can't be solved since the determinant is negative.
Explanation:
#CarryOnLearning
10. Why is it important to make an illustration of the problem first before solving the actual problem of projectile motion?
Answer:
Identify and explain the properties of a projectile, such as acceleration due to gravity, range, maximum height, and trajectory.
Determine the location and velocity of a projectile at different points in its trajectory.
Apply the principle of independence of motion to solve projectile motion problems.
11. PROJECTILE MDEFINE PROJECTILE MOTION:
Answer:
Projectile motion is a form of motion experienced by a launched object. Ballistics is the science of dynamics that deals with the flight, behavior and effects of projectiles, especially bullets, unguided ...
12. what is the difference between half projectile motion and full projectile motion?
Answer:
A projectile is any object upon which the only force is gravity, Projectiles travel with a parabolic trajectory due to the influence of gravity, ... The vertical velocity of a projectile changes by 9.8 m/s each second, The horizontal motion of a projectile is independent of its vertical motion.
Explanation:
hope itz help
13. It's a projectile motion problem. Please help huhu
38 m/s
Do you need the formula?
14. PA HELP PROJECTILE MOTION PA GRESA METHOD A AND B PROBLEMS
Answer:
hell lol the following statements
15. 5. Before beginning projectile motion problems, you need to? A. Split the horizontal and vertical motion. B. Consider the impact of air resistance C. Solve for the acceleration due to gravity D. Determine the surface area of a projectile.
Explanation:
D. Determine the surface area of a projectile.
16. Create a problem about projectile motion and provide a solution
Answer:
Physics
Are some projectile motion problems unsolvable?
Asked 5 years, 8 months ago
Modified 4 years, 5 months ago
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I am working on a project which involves launching a tennis ball at a certain velocity and angle in order to hit a given target. To do so, I have just started diving into projectile motion and am thus a beginner in this field. However, manipulating the basic equations to get results is pretty straight forward in most cases.
My problem: I have implemented a solver that calculates the needed launch angle for given initial projectile velocity, position of launcher and position of target in order to reach the target. I found out that the solutions to this problem are the roots of following quadratic equation :
0=12gΔ2xv20tan2(θ)−Δxtan(θ)+12gΔ2xv20tan2(θ)−Δy
where y is the height of the target, y0 is the height of the launcher, Δy=y−y0, and similarly for x, x0, and Δx. θ, v0, and g are, respectively, the launch angle, the initial velocity and gravitational acceleration.
Given that the unknown X that we are solving for is defined as X=tan(θ), the roots can be expressed as
v20±v40−g(gΔ2x+2Δyv20)−−−−−−−−−−−−−−−−−√gΔx
Now here is the tricky part: when I input the values of a similar problem I found on the internet (Δx=600 m, Δy=40 m, v0=100 m/s), I find the exact same angles as the solutions stated in this problem. However, when I input random values, I almost always get imaginary solutions. For example Δx=30 m, Δy=0 m, v0=10 m/s can't be solved since the determinant is negative.
pa follow ty
17. A basketball shoot to a ringProjectile motion or non projectile motion
Answer:
projectile motion
Explanation:
that's the answr
Answer:
3 point shot bengbeng
Explanation:
pasuk
18. 1 LEARNING TASK #1Directions: Based on the picture, determine which is an example of a projectile motion andwhich is not. Write projectile motion or not projectile motion on the space provided for eachnumber.
Answer:
1. Projectile Motion
2. Projectile Motion
3. Not Projectile Motion
4. Projectile Motion
5. Not Projectile Motion
19. What is Horizontal Projectile Motion? Vertical Projectile Motion?
Answer:
The horizontal velocity of a projectile is constant (a never changing in value), There is a vertical acceleration caused by gravity; its value is 9.8 m/s/s, down, The vertical velocity of a projectile changes by 9.8 m/s each second, The horizontal motion of a projectile is independent of its vertical motion.
20. Galilean of vertical motion, horizontal motion and projectile motion
Answer:
Galileo on Projectiles
Beginning on page 244 of Two New Sciences, Galileo gives his classic analysis of the motion of a projectile as a compound motion, made up of a horizontal motion which has steady speed in a fixed direction, and a vertical motion which is his "naturally accelerated motion" picking up velocity in the downward direction at a steady rate. Don't worry about the bits of Greek geometry mentioned near the beginning, I've left in one or two remarks to give the flavor, but cut out the main argument - we shall just take a parabola to be defined as y proportional to x2.
It is interesting to note the difficulties raised towards the end, and Galileo's rebuttals. It is noted that, when Galileo asserts that a frictionless ball on a truly flat plane with no air resistance would roll on forever, Simp points out that going far enough on a really flat plane would mean moving away from the earth, in other words, it would become "uphill". Galileo admits this effect exists, but just claims it is a negligible correction, even for projectiles going four miles, apparently the furthest anything had been shot at the time.
Galileo shows a modern scientific attitude in realizing that his results are not exact, but that that need not be important. The main thing is to be sure how large the errors are, and thus whether or not they matter for the task at hand. This is very different from the attitude of Greek geometers, who were only interested in precise results - yet Galileo's is the only way in which their work can be used to understand the real physical world.
21. Performance tasks#1 Types and parts of projectile motion A. Match the picture on the type of projectile motion.
where's the picture?
how can we answer that?
22. motion of the earth around the sun it is projectile or not projectile
Answer:
it's projectile
Explanation:
iwan basta nag sagot ako tapos.
Answer:
you can consider it as a projectile
Explanation:
because being a projectile means there is at least one factor that affects the object for it to move
, in this case, the sun is is that object and the earth was veing launch by the sun's gravity making it move,revolve, go incircle to the sun
23. can someone give me a example of projectile motion Problem Show process
Answer:
an object intended to be or having been fired from a weapon.
24. What is the main characteristics difference between horizontal projectile motion and vertical projectile motion
Answer:
The horizontal velocity of a projectile is constant (a never changing in value),
There is a vertical acceleration caused by gravity; its value is 9.8 m/s/s, down,
The vertical velocity of a projectile changes by 9.8 m/s each second,
The horizontal motion of a projectile is independent of its vertical motion.
Explanation:
hope it helps.
25. Solve the given problems involving the motion of objects in a projectile.
Answer:
► Proyekto
Magsaliksik ng isang editoryal tungkol sa pandemnya. Gumawa ng komiks o iskit tungkol sa editoryal na iyong nakalap. Gumamit ng paghahambing ng salita, mga tindi at antas nito tungo sa higit na malalim na pagkakaunawa at pagkatuto.
26. Direction: Complete the table by solving the components of the projectile motion. Projectile Component of Projectile Motion 1.Ball thrown at 30°
It will become 20° because....
27. Learning Task 1: Projectile MotionRead each sentence. Write True if the statement is correct and False if it isincorrect.1. A projectile motion has a constant velocity in the horizontal direction.2. The velocity at the maximum height of a projectile motion is not equal to zero.3. The path of the projectile motion is called a trajectory.4. A force acting on a projectile is gravity.-5. The gravity at the maximum height of a projectile motion is zero.
Answer:
1.False
2.True
3.True
4.True
5.True
Explanation:
hope it helps
28. why is it important to study projectile motion? give at least three examples of projectile motion application
Answer:
By studying the motion of things traveling in the air, also known as projectiles, we can figure out just how fast the food needs to be launched in order for it to get to them.
Explanation:
SANA NAKA TULONG PO AKO PA BRAINLEIST PO...
29. solve the following problems in projectile motion. Show your solution.
Answer:
I can control my power now
Explanation:
nana
30. Write if true or false1. A projectile motion has constant velocity in the horizontal direction.2. The velocity at the maximum height of a projectile motion is not equal to zero.3. The path of the projectile motion is called a trajectory.4. A force acting on a projectile is gravity.5. The gravity at the maximum height of a projectile motion is zero.
Answer:
1.true 2.true 3.false 4.true 5.false
Explanation:
hope it helps
Answer:
1. true
2.true
3.false
4. false
5. true
Explanation:
sna maka tulong
