what is the chemical formula of carbohydrates and phosphorus?
1. what is the chemical formula of carbohydrates and phosphorus?
Carbohydrates - CH2O
(Yung 2 nasa baba ng H yung parang sa H2O lang)
Phosphorus - there is no chemical formula for phosphorus because it is an element which is the symbol for it is "P"
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Hope this helps! :)
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2. What is the Molecular formula of the following, Phosphorus triiodide Tetramanganese dihydride Trilithium hexasulfide Decaberyllium heptafluoride Hexasilver dichloride Octamagnesium hexasulfide Heptazinc pentanitride Pentaaluminum decabromide Nonalead octaphosphoride
Phosphorus triiodide-PI3
Tetra-manganese dihydride-H2Mn
Trilithium hexasulfide- H2Li3N+2
Decaberyllium heptafluoride- BeF2
Hexasilver dichloride- AgC1
That’s all I can answer sorry
3. Write the formulas for the following convalent compounds:1. Antimony tribromine2. Hexaboron silicide3. Chlorine Dioxide 4. Hydrogen Iodide5. Iodine Pentafluoride 6. Dinitrogen trioxide 7. ammonia8. Phosphorus triiodide
Answer:
1. SbBr3
2. B6Si
3. ClO₂
4. HI
5. IF5
6. N2O3
7. NH3
8. PI3
4. What are chemical symbol for elements with long names such as beryllium, phosphorus and germanium
Answer:
Be
P
Ge
Chemical Symbiols
Answer:
Beryllium is (Be)
Phosphorus is (P)
Germanium is (Ge)
Explanation:
pls trust me also just pm me how to know the chemical names of any element tnx
5. What is the chemical formula, lewis dot symbol and lewis dot structure of boron trichloride, Phosphorus tribromide, sulfur dioxide, dinitrogen monoxide and tetrabarium hexachloride
Answer:
Thus far in this chapter, we have discussed the various types of bonds that form between atoms and/or ions. In all cases, these bonds involve the sharing or transfer of valence shell electrons between atoms. In this section, we will explore the typical method for depicting valence shell electrons and chemical bonds, namely Lewis symbols and Lewis structures.Lewis SymbolsExplanation:
BRAINLIESTExplanation:
sana makahelp po sainyo
6. TOPIC: ELEMENTS AND COMPOUNDS ACTIVITY NO: 1 TITLE OF ACTIVITY: ELEMENTS OR COMPOUNDS Instructions/Procedures: Complete the Table by filling-in the chemical symbol or formula, composition and classification of substance as element or compound) CHEMICAL NAME 1. Tungsten 2. Acetic acid 3. Glass 4.phosphorus 5. Lactic acid 6. Gold 7. Carbon dioxide 8. Ice 9. Lime (apog) 10. Carbon 11. Water 12. Aluminum foil CHEMICAL SYMBOL OR FORMULA W COMPOSITION (TYPES AND NUMBER OF ELEMENTS PRESENT) TYPE OF SUBSTANCE METAL
Explanation:
there is the answer sorry i don't know to how to answer the composition types number of elements present
correct me of I'm wrong thankyou
7. 10. How many mole of Phosphorus (III) oxide( P203) was produced by the chemical reaction?
Answer:
this is science or math
Explanation:
this is science or math
8. Can you answer this:Choices:Pollutionbasinsrocks and mineralswasteDNAovergrowthplants1. Phosphorus is NOT found in the Free State in Nature, but is contained mostly in________and______2. It is an essential nutrient for life, as it makes up important chemicals such as_____3.In the Phosphorus Cycle,phosphorus moves between the so and ______,which are eaten by animals. The animals use phosphorus, and then their_______ products help return the Sulfur for the next generation of phosphorus in the soil.4.Some of the phosphorus in soil can be washed away into water______. 5.Another source of phosphorus in water comes from man-made ______.6.Too much phosphorus in water leads to plants ________,strangling all other life forms in the water.Subject:Environmental Science
Answer:
1.rocks and minerals
2.pollution
3.waste, basins
4.plants
5.DNA
6.Over growth
Explanation:
here are your answers on your questions
Answer:
1.rock and minerals
2.DNA
3.plants;waste
4.pollution
5.Basins
6.overgrowth
9. a sample of mass contains 43.6g phosphorus and 54.4g oxygen. what is the empirical formula
Solution:
Step 1: Calculate the number of moles of each element.
[tex]n \: \text{P = 43.6 g} × \frac{\text{1 mol}}{\text{30.97 g}} = \text{1.4078 mol}[/tex]
[tex]n \: \text{O = 56.4 g} × \frac{\text{1 mol}}{\text{16.00 g}} = \text{3.525 mol}[/tex]
Step 2: Represent an empirical formula.
[tex]\text{empirical formula} = \text{P}_{x}\text{O}_{y}[/tex]
Step 3: Divide the number of moles of each element by the least number of moles.
[tex]x = \frac{\text{1.4078 mol}}{\text{1.4078 mol}} = 1 × 2 = 2[/tex]
[tex]y = \frac{\text{3.525 mol}}{\text{1.4078 mol}} = 2.5 × 2 = 5[/tex]
Step 4: Write the empirical formula.
[tex]\boxed{\text{empirical formula} = \text{P}_{2}\text{O}_{5}}[/tex]
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10. Compound Chemical Formula Structural Formula +- Ball-and-Stick Modelcarbon monoxide phosphorus trihydride nitrous oxide hydrochloric acid sodium hydroxide
Carbon monoxide CO
Phosphorus trihydride PH3
Nitrous oxide N2O
Hydrochloric acid HCl
Sodium hydroxide NaOH
11. What is the empirical and molecular formula of a substance containing 43.64% phosphorus and 56. 36% oxygen by mass? Its molecular mass is 141.9g
SOLUTION: (Empirical Formula)
Step 1: Assume that the mass of a compound is 100 g.
[tex]\begin{aligned} & mass_{\text{P}} = \text{43.64 g} \\ & mass_{\text{O}} = \text{56.36 g} \end{aligned}[/tex]
Step 2: Calculate the number of moles of each element.
[tex]\begin{aligned} & n_{\text{P}} = \text{43.64 g} \times \frac{\text{1 mol}}{\text{30.97 g}} = \text{1.409 mol} \\ & n_{\text{O}} = \text{56.36 g} \times \frac{\text{1 mol}}{\text{16.00 g}} = \text{3.5225 mol} \end{aligned}[/tex]
Step 3: Represent an empirical formula.
[tex]\text{empirical formula} = \text{P}_x\text{O}_y[/tex]
Step 4: Divide the moles of each element by the least number of moles.
In this case, the least number of moles is 1.409 mol.
[tex]\begin{aligned} & x = \frac{\text{1.409 mol}}{\text{1.409 mol}} = 1 \\ & y = \frac{\text{3.5225 mol}}{\text{1.409 mol}} = 2.5 \end{aligned}[/tex]
Step 5: Multiply the subscripts obtained by a certain number to become whole number.
Since the decimal part of 2.5 is 0.5, we need to multiply all the subscripts by 2. Therefore,
[tex]\begin{aligned} & x = 1 \times 2 = 2 \\ & y = 2.5 \times 2 = 5 \end{aligned}[/tex]
Step 6: Write the empirical formula.
[tex]\text{empirical formula} = \boxed{\text{P}_2\text{O}_5}[/tex]
Hence, the empirical formula of a substance is P₂O₅.
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SOLUTION: (Molecular Formula)Step 1: Represent a molecular formula.
[tex]\text{molecular formula} = (\text{P}_2\text{O}_5)_n[/tex]
Step 2: Calculate the empirical mass.
[tex]\begin{aligned} \text{empirical mass} & = \text{2(30.97 g) + 5(16.00 g)} \\ & = \text{61.94 g + 80.00 g} \\ & = \text{141.9 g} \end{aligned}[/tex]
Step 3: Divide the molecular mass by the empirical mass to find the value of n.
[tex]\begin{aligned} n & = \frac{\text{molecular mass}}{\text{empirical mass}} \\ & = \frac{\text{141.9 g}}{\text{141.9 g}} \\ & = 1 \end{aligned}[/tex]
Step 4: Multiply the subscripts by the value of n to obtain the molecular formula.
[tex]\begin{aligned} \text{molecular formula} & = (\text{P}_2\text{O}_5)_1 \\ & = \boxed{\text{P}_2\text{O}_5} \end{aligned}[/tex]
Hence, the molecular formula of a substance is P₂O₅.
12. 2. The reaction between solid white phosphorus and oxygen produces solidtetraphosphorusdecoxide (P4010).a. Write the balanced chemical equation of the reaction.
Answer:
solid will be gassolid can be returned to gassolidExplanation:
mm
13. give the chemical formula of the following compound then calculate for the molar mass of each 26.Aluminum + Chlorine. 27.Magnesium + Phosphate 28. Iron(111) + Oxygen. 29.Sodium + Sulfite 30.Calcium + Phosphorus
Answer:
26. AlCl₃
27. Mg3(PO4)2
28. Fe2O3
29. Na2SO3
30. Ca3(PO4)2
⠀
14. what is the formula of phosphorus trioxide
Phosphorus trioxide is the chemical compound with the molecular formula P 4 O 6. Although the molecular formula suggests the name tetraphosphorus hexoxide, the name phosphorus trioxide preceded the knowledge of the compound's molecular structure, and its usage continues today. This colorless solid is structurally related to adamantane
just check the photo thats the answer hope it helps pa mark nalang ng brainliest ty po <3
15. 1. Two acids is reacted, phosphoric acid and hydrochloric acid yield to phosphorus pentachloride and water write formula
Answer:
H₃PO₄ + 5HCl → PCl₅ + 4H₂O
Explanation:A chemical equation is a representation of a chemical reaction, wherein the reactants are written on the left side and the products on the right side of a chemical equation.
In writing a chemical equation, the chemical names of substances involved in a chemical reaction are written in symbolic form. If you do not know how to write the chemical formula of a substance, kindly refer to the topic "Chemical Formula Writing".
The word "and" in the statement above will be replaced by the plus (+) symbol. When you also see the word "reacted with" or "combined with" , it will also replaced by the plus (+) symbol.
The word "yield" will be substituted by the right arrow (→) symbol. Other keywords for the word "yield" are "produced", "obtained", etc.
Therefore, the statement, when replaced with symbols and formulas, becomes
H₃PO₄ + HCl → PCl₅ + H₂O
In balancing chemical equations, you must keep in mind that the number of each atom in the reactant side must be equal to the number of each atom in the product side in accordance with the Law of Conservation of Mass.
The balanced chemical equation now becomes
[tex]\boxed{\text{H₃PO₄ + 5HCl → PCl₅ + 4H₂O}}[/tex]
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16. Compound Name 1. Carbon dioxide 2. Carbon monoxide 3. Dephosphorus 4 Denetrogen monoxide pentaxide 5. Silicon dioxide 6. Carbon tetrabromide 7. Sulfur dioxide 8 Phosphorus pentrabromide 9.iodine trichloride10.nitrogen triiodide11.Dinitrogen trioxideCompound Formula1.CO2-----2.CO-----3.P2o----4.N20----5.S10----6.CBR4----7.SO2-----8.Pbro----9.icL----10.n13----11.n203-----
Answer:
1.)1s²2s²2p²
hula is the key
17. What is the empirical formula of a compound containing 43.6% phosphorus and 56.4% oxygen?
Answer:
The empirical formula for a compound that is 43.6% phosphorus and 56.4% oxygen is P2O5. In the formula, the P stands for phosphorus and the O standards for oxygen, so there are 2 phosphorus (P) atoms and 5 oxygen (O) atoms in the compound. The atomic mass of phosphorus (P) is 30.974 u and the atomic mass of oxygen (O) is 15.999 u.
Explanation: wala na nun
18. Rule: Name of the cation + root name of the anion-ide/ Write the name of the metal + change the end of nonmetal with -ide.Elements CombinedEx. Sodium and BromineTungsten and sulfurMagnesium andphosphorusSymbols ofelements combinedNa + Br₂Al + F₂Criscross of oxidationnumbersNattBr₂1Chemical formulaNaBrAgClChemical nameSodium chlorideZinc nitride
Answer:
Explanation:
Tungsten and sulfur:
+Symbols of elements combined: W + S
+Crisscross of oxidation numbers: W₂S₆
+Chemical formula: WS₃
+Chemical name: Tungsten (III) sulfide
+Magnesium and phosphorus:
+Symbols of elements combined: Mg + P
+Crisscross of oxidation numbers: Mg₃P₂
+Chemical formula: Mg₃P₂
+Chemical name: Magnesium phosphide
19. Write the formula for the following convalent compounds: 1. Antimony Tribromine 2. Hexaboron Silicide 3. Chlorine Dioxide 4. Hydrogen Iodide 5. Iodide Pentafluoride 6. Dinitrogen trioxide 7. Ammonia 8. Phosphorus Triiodide
Explanation:
nasa picture napo ang answer
hope it helps
20. Write the chemical formula of the following covalent compounds. Example: dinitrogen tetrahydride - N2 HA 1. Carbon dioxide 2. Hydrogen dioxide (water)3. Phosphorus trichloride 4. Carbon tetrachloride 5. Nitrogen trifluoride
EVERYBODY LOVES SCIENCE LIKE I DO ^_^
21. what is the formula of the compound formed by barium and phosphorus?
Answer:
Barium phosphate | Ba3(PO4)2 - PubChem.
22. B. Directions: Analyze the given chemical reaction then answer the questions that follow. (15 pts) "The element Magnesium reacts with Phosphate". What will be the chemical equation for this reaction? What are the reactants in this chemical reaction? How about the product that will be formed after the reaction? Write the chemical formula for the product formed. How many atoms of Magnesium will be present in the product? How many atoms of Phosphorus are present in the product formed? How many atoms of Oxygen will be formed after the reaction?
where is it found?
Explanation:
i dont know where it found
23. what is the empirical formula of a compound consisting of 42.07% sodium,18.89% phosphorus and 39.04% oxygen
Answer:
P=18.89%)
Sana po nakatulong.
Paki brainliest po.
Maraming salamat po.
24. The empirical formula of a compound of phosphorus and oxygen was found to be P2O5. Experimentation shows that the molar mass of this compound is 283.89g/mol. What is the compound’s molecular formula?
The compound’s molecular formula : P₄O₁₀
Further explanationThe empirical formula (EF) is the smallest comparison of atoms of compound forming elements.
A molecular formula (MF) is a formula that shows the number of atomic elements that make up a compound.
(empirical formula) n = molecular formula
(EF)n=MF
The empirical formula (EF) of compound : P₂O₅
The compound has a molar mass of 283.89 g/mol ⇒ Mf = 283.89
(EF)n = MF
(P₂O₅)n=283.889
(2 x 30.973762 + 5 x 15.999)n = 283.889
(141.9425)n=283.89 ⇒ n = 1.99≅2
So the molecular formula (MF) : P₄O₁₀
Learn moreThe molecular formula of the alcohol :C₃H₈O (propanol)
https://brainly.ph/question/1495277
The molecular formula of Terephthalic acid : C₈H₆O₄
https://brainly.ph/question/2737648
molar mass
brainly.ph/question/826345
#LetsStudy
25. chemical behavior of phosphorus
White phosphorus is a waxy, transparent solid. Its melting point is 44.1°C (111°F) and its boiling point is 280°C (536°F). It has a density of 1.88 grams per cubic centimeter. If kept in a vacuum, it sublimes if exposed to light.
What are the characteristics of phosphates?
Phosphorus (P), nonmetallic chemical element of the nitrogen family (Group 15 [Va] of the periodic table) that at room temperature is a colourless, semitransparent, soft, waxy solid that glows in the dark.
What chemical family is phosphorus in?
Nonmetal
Pnictogen
Period 3 element
Phosphorus/Chemical series
Why is phosphorus called the devil's element?
Phosphorus was discovered in 1669 by Hennig Brand in Germany. ... Only the white allotrope or form of phosphorus glows in the dark. Some texts refer to phosphorus as the "Devil's Element" because of its eerie glow, tendency to burst into flame, and because it was the 13th known element.
26. what is the chemical symbol of element phosphorus?a. Phb. Fec. Pd. F
Answer:
The answer is letter C. P
Answer:
THE ANSWER IS LETTER C. P IS THE SYMBOL OF PHOSPHORUS
Explanation:
HOPE IT HELPS
27. Determine the molecular formula of the following compounds, given their molar masses. Show complete solutions. What is the empirical formula and molecular formula for lactic acid if the percent composition is 40.00% C, 6.71% H, 53.29% O, and the approximate molar mass is 90 g/mol? A sample of a compound with a formula mass of 34.00 g/mol is found to consist of 0.44 g H and 6.92 g O. Find its molecular formula. A 1.000 g sample of red phosphorus powder was burned in air and reacted with oxygen gas to give 2.291 g of a phosphorus oxide. Calculate the empirical formula and molecular formula of the phosphorus oxide given the molar mass is approximately 284 g/mol
Answer:
1.) empirical: [tex]C_{3}H_{6}O_{3}[/tex], molecular: [tex]CH_{3}CHCOOH[/tex]
2.) [tex]H_{2} O_{2}[/tex]
3.) molecular: [tex]P_{4} O_{10}[/tex], empirical: [tex]P_{2}O_{5}[/tex]
Explanation:
1.) Given: 40.00% C, 6.71% H, 53.29% O; approx. MM = 90 g/mol
To get the empirical formula (the simplest whole number ratio of the elements that composes lactic acid):
Assume a mole of lactic acid; refer to periodic table for the approx. molar masses of C, H, and O:
90 g (0.40) = 36 g of C /mol of Lactic acid
(36 g of C/mol of Lactic acid) / (12 g/mol C) = 3 mol of C / mol of Lactic acid
90 g (0.0671) = 6.039 g of H/mol of Lactic acid
(6.039 g of H/mol of Lactic acid) / (1 g/mol H) = 6.039 mol of H/mol of Lactic acid = 6 mol of H/mol of Lactic acid
90 g (0.5329) = 47.961 g of O/mol of Lactic acid
(47.961 g of O/mol of Lactic acid)/ (16g/mol O) = 2.998 mol of O/mol of Lactic acid = 3 mol of O/ mol of Lactic acid;
Therefore, the empirical formula would be: [tex]C_{3}H_{6}O_{3}[/tex]
To find the molecular formula, we divide the approximate molar mass by the empirical formula mass. In this problem, they are equal, so we further refer to the IUPAC conventions of naming organic compounds.
The given substance is a carboxylic acid, so the suffix is -COOH. For the prefix, carboxy, we refer to what remains in our empirical formula, still following the convention of a maximum of 3 hydrogen's attached to a carbon in a chain, CH₃CH - .
Therefore, the molecular formula would be: [tex]CH_{3}CHCOOH[/tex].
2.) Given: 'formula' mass = 34.00 g/mol; 0.44 g H and 6.92 g O
First, we determine the number of moles of each element present in the compound:
0.44 g H in compound/ (1 g/mol H) = 0.44 mol H in compound
6.92 g O in compound/ (16 g/mol O) =0.4325 mol O in compound
ratio = [tex]\frac{0.44 mol H}{0.4325 mol O}[/tex] = 1.017 mol H/mol O or 1:1
This means that the empirical formula is HO and that the empirical formula mass is 17 g/mol.
To determine the molecular mass, we determine the ratio of the obtained empirical mass and the given molecular mass:
ratio = [tex]\frac{34 g/mol}{17g/mol}[/tex] = 2
Therefore, the molecular formula is [tex]H_{2}O_{2}[/tex].
3.) Given: 1.000 g sample red phosphorus powder reactant; 2.291 g Phosphorus Oxide product; approx. molar mass = 284 g/mol
First, we get the moles of phosphorus oxide produced and the moles of phosphorus consumed (assuming the powder is 100% phosphorus):
[tex]n = \frac{2.291 g}{284g/mol} = 8.067x10^{-3} mol[/tex] phosphorus oxide
[tex]n = \frac{1.000g}{31 g/mol} = 0.0323 mol[/tex] phosphorus
We must take note that the phosphorus powder reacted with oxygen gas and that oxygen gas exists in the form of [tex]O_{2}[/tex].
[tex]ratio = \frac{ 0.0323 mol }{8.067x10^{-3}mol} = 4.004 mol[/tex] phosphorus/ mol phosphorus oxide
From there, we can express it in a 'tentative' chemical equation (based on the situation):
[tex]4P + O_{2} => P_{x}O_{y}[/tex]
We can deduce from the equation that [tex]x= 4[/tex] based on the left side and on the ratio. Then, to get [tex]y[/tex], we can use the approximate molar mass:
[tex]y=\frac{284g/mol-(4)(31g/mol) }{16g/mol O} = 10[/tex]
Therefore, the molecular formula is [tex]P_{4}O_{10}[/tex].
Then, to get the empirical formula, we reduce both coefficients, x and y, to lowest terms.
Therefore, the empirical formula is [tex]P_{2} O_{5}[/tex].
NOTE: Let's go back to our 'tentative' chemical equation. Since the empirical formula is used in expressing chemical reactions, our final balanced equation would be:
[tex]4P + 5O_{2} => 2P_{2}O_{5}[/tex]
28. Write a chemical equation representing the burning of carbon: carbon; phosphorus; sulfur; Hidro and read the name of the product
Answer:
The chemical equation for the burning of carbon in the presence of oxygen is:
C + O2 -> CO2
The product of this reaction is carbon dioxide.
Similarly, the chemical equation for the burning of phosphorus in the presence of oxygen is:
P4 + 5O2 -> 2P2O5
The product of this reaction is diphosphorus pentoxide.
The chemical equation for the burning of sulfur in the presence of oxygen is:
S + O2 -> SO2
The product of this reaction is sulfur dioxide.
The chemical equation for the burning of hydrogen in the presence of oxygen is:
2H2 + O2 -> 2H2O
The product of this reaction is water.
29. Activity 2: Use Lewis structure to show the IONIC BINDING in the following pairs of elements. Show the transfer of electrons using arrows. Write the correct chemical formula for the ionic compound that forms.• Sodium Nitride (Na and N)Chemical Formula:• Sodium Oxide (Na and O)Chemical Formula:• Calcium Chloride (Ca and Cl)Chemical Formula:Activity 3: Use Lewis dot structures to show the COVALENT BONDING in the following pairs of elements. Once you have determined the structure for the molecule, write its structural formula in the space provided; use a dash to represent a shared pair of electrons, and dots to show unshared electrons.Nitrogen Triiodide (NI3)Show work here... Hint: Nitrogen is in the middle!Carbon Tetrabromide (CBr4)Show work here... Hint: Carbon is in the middle!Dihydrogen Monoxide (H2O)Show work here... Hint: Oxygen is in the middle!Write your answer in another sheet of paper then picture and paste the attachment for your answer to this question.
Explanation:
Sana naiintindihan mo ho sulat ko. Amen.
30. what is the molecular formula of 1. disphosphorus pentoxide2.trisulfur hexafluoride3.nitrogen triiodide4.carbon monoxide5. sulfur dioxidepls need asap
Answer:This is the case with diphosphorus pentoxide. It has a molecular formula of P4O10, however, its name diphosphorus pentoxide comes from its empirical formula P2O5 (“di-“=2, “pent-“=5). Molecular Formula Cl2S3 Nitrogen triiodide is the inorganic compound with the formula NI3. It is an extremely sensitive contact explosive. CO SO₂
HOPE THIS HELPS!
#CarryOnLearning what is the molecular formula of disphosphorus pentoxideThis is the case with diphosphorus pentoxide. It has a molecular formula of P4O10, however, its name diphosphorus pentoxide comes from its empirical formula P2O5 (“di-“=2, “pent-“=5).
what is the molecular formula of trisulfur hexafluorideTrisulfur Pentabromide S3Br5 Molecular Weight
what is the molecular formula of nitrogen triiodideNitrogen triiodide is the inorganic compound with the formula NI3. It is an extremely sensitive contact explosive.
what is the molecular formula of carbon monoxideCarbon monoxide is a colorless, odorless, tasteless gas. A molecule of carbon monoxide (CO) contains one carbon atom and one oxygen atom. ... In the colored models, carbon is light gray and oxygen is red. Carbon monoxide is flammable and is quite toxic to humans and other oxygen-breathing organisms.
what is the molecular formula of sulfur dioxide(SO₂)[tex]\rm\orange{\overbrace{\underbrace{\tt\color{blue}{ \: \: \: \: \: \: \: \: HOPE \: \: IT'S \: \: HELP \: \: \: \: \: \: \: \: }}}}[/tex]
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