Rhodium has an FCC crystal structure, an atomic radius of 0.1345 nm and atomic weight of 102.9 g/mol. Calculate the density of rhodium.
1. Rhodium has an FCC crystal structure, an atomic radius of 0.1345 nm and atomic weight of 102.9 g/mol. Calculate the density of rhodium.
[tex]\tt{\huge{\red{Solution:}}}[/tex]
Step 1: Calculate the edge length of the unit cell.
[tex]\begin{aligned} a & = \sqrt{8} \times r \\ & = \sqrt{8} \times \text{0.1345 nm} \\ & = \text{0.38042 nm} \\ & = 0.38042 \: \cancel{\text{nm}} \times \frac{1 \times 10^{-9} \: \cancel{\text{m}}}{1 \: \cancel{\text{nm}}} \times \frac{\text{100 cm}}{1 \: \cancel{\text{m}}} \\ & = 3.8042 \times 10^{-8} \: \text{cm} \end{aligned}[/tex]
Step 2: Calculate the volume of the unit cell.
[tex]\begin{aligned} V & = a^3 \\ & = (3.8042 \times 10^{-8} \: \text{cm})^3 \\ & = 5.5054 \times 10^{-23} \: \text{cm}^3 \end{aligned}[/tex]
Step 3: Calculate the mass the unit cell (m).
Note that in a face-centered cubic crystal structure, there are 4 atoms in a unit cell.
[tex]\begin{aligned} m & = 4 \: \cancel{\text{atoms}} \times \frac{1 \: \cancel{\text{mol}}}{6.022 \times 10^{23} \: \cancel{\text{atoms}}} \times \frac{\text{102.9 g}}{1 \: \cancel{\text{mol}}} \\ & = 6.8349 \times 10^{-22} \: \text{g} \end{aligned}[/tex]
Final Step: Calculate the density of rhodium.
[tex]\begin{aligned} d & = \frac{m}{V} \\ & = \frac{6.8349 \times 10^{-22} \: \text{g}}{5.5054 \times 10^{-23} \: \text{cm}^3} \\ & = \boxed{\text{12.41 g/cm}^3} \end{aligned}[/tex]
Hence, the density of rhodium is 12.41 g/cm³.
[tex]\\[/tex]
Note: Kindly swipe the screen to the left to see the continuation of the answer on the right side.[tex]\\[/tex]
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2. Calculate the radius of a palladium atom, given that Pd has an FCC crystal structure, a density of 12.0 g/cm3, and an atomic weight of 106.4 g/mol.
Answer:
Calculate the radius of a palladium atom, given that Pd has an FCC crystal structure, a density of 12.0 {eq}g/cm^3 {/eq}, and an atomic weight of 106.4 {eq}g/mol {/eq}.
Face-Centered Cubic Unit Cell:
Atoms are present in all of the crystal lattice's corner positions in the FCC unit cell. In the middle of each face of the cube, there is also an atom. The relation between radius and edge length for FCC unit cell is:
{eq}a = \dfrac{{4r}}{{\sqrt 2 }} {/eq}
yan po
Question:Calculate the radius of a palladium atom, given that Pd has an FCC crystal structure, a density of 12.0
g
/
c
m
3
, and an atomic weight of 106.4
g
/
m
o
l
.
Face-Centered Cubic Unit Cell:
Atoms are present in all of the crystal lattice's corner positions in the FCC unit cell. In the middle of each face of the cube, there is also an atom. The relation between radius and edge length for FCC unit cell is:
a
=
4
r
√
2
3. The atomic weight, density, and atomic radius for the two hypothetical alloys are listed in the given table. for each, determine whether its crystal is fcc, bcc or simple cubic.
Answer:
Results (12676)
Explanation:
according to my research
4. what is the density in g/l of nitrogen dioxide at 100°c and
Answer:
The density of nitrogen dioxide at 100°C is approximately 6.3 g/L. This value can vary slightly depending on the specific conditions of the gas, such as its pressure and humidity.
It's important to note that the density of a gas is not a constant value, but rather it is dependent on temperature and pressure. As a result, the density of nitrogen dioxide may be different at other temperatures and pressures.
Explanation:
Certainly! Here are a few possible solutions for determining the density of nitrogen dioxide at 100°C:
Use a density meter: A density meter is a device that can measure the density of a gas or liquid. To use a density meter to measure the density of nitrogen dioxide at 100°C, you would need to first ensure that the device is calibrated to measure gases at that temperature. Then, you would need to carefully measure out a known volume of nitrogen dioxide and use the density meter to determine its density.Look up the density in a reference table: Some reference tables, such as the properties of common gases tables found in chemistry textbooks or online, list the densities of various gases at different temperatures and pressures. If you can find a reference table that lists the density of nitrogen dioxide at 100°C, you can use this value as an approximate density for the gas under those conditions.Use the ideal gas law: The ideal gas law is a mathematical equation that can be used to calculate the density of a gas under certain conditions. The equation is:D = (P * M) / (R * T)Where D is the density of the gas, P is the pressure of the gas, M is the molecular weight of the gas, R is the gas constant, and T is the temperature of the gas. If you know the values of P, M, R, and T for nitrogen dioxide at 100°C, you can use this equation to calculate the density of the gas under those conditions.I hope these suggestions are helpful!
5. using the given formula on population density, compute for the population density of 100 frogs in a 500 square meters farm
Population density is 2 frogs per squared meter.
Explanation:
Step 1: Enumerate the given values.Given:
n = 100 frogs
A = 500 m²
Step 2: Identify what is being asked.Required:
Population density
Step 3: Solve for Population densitySolution:
The formula for work is given by:
PD = n/A
where: PD - Population Density
n - number of inhabitants
A - land area
Substituting the value of n and A in the formula,
PD = (100 frogs)/(500 m²)
PD = 2 frogs/m²
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6. Nickel has a FCC crystal structure, an atomic radius of 0.125 nm, and an atomic weight of 58.68 g/mol. Compute and compare its theoretical density with the experimental value of 8.90 g/cm3.
Answer:
d = 8.82 g/cm³
The theoretical density differs from the experimental density by 0.08 g/cm³. The value of theoretical density is near to the value of experimantal density
Explanation:
Note: Nickel has a FCC crystal structure
Converting nm to cm
R = 0.125 nm × (1 × 10^(-9) m / 1 nm) × (100 cm / 1 m)
R = 1.25 × 10^(-8) cm
Calculating the volume of the unit cell
V = a³ = (2√2 R)³ = 16√2 R³
V = 16√2 (1.25 × 10^(-8) cm)³
V = 4.41942 × 10^(-23) cm³
Calculating the mass of nickel
m = 58.68 g/mol × (1 mol / 6.02214 × 10²³ atoms) × 4 atoms
m = 3.89762 × 10^(-22) g
Calculating the theoretical density
d = m / V
d = 3.89762 × 10^(-22) g / 4.41942 × 10^(-23) cm³
d = 8.82 g/cm³
Comparing the theoretical density to experimental density
The theoretical density differs from the experimental density by 0.08 g/cm³. The value of theoretical density is near to the value of experimantal density.
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7. Platinum has a density of 21.45 g/ml .Gold has a density of 19.28 g/ml Wich is larger, a 100 gram cube of platinum or 100 gram cube of gold. Expleain yoour answer
Answer:
100 gram cube of gold.
Explanation:
Find the volume of each.
Platinum: 100.0 g x 1 ml/21.45 g = 4.662 ml
Gold: 100.0 g x 1 ml/19.28 g = 5.187 ml
So, if by larger you mean which has a greater volume, then the answer is Gold.
Answer:
Gold.
Explanation:
"Platinum"
100grams of cube of platinum × 1ml/ 21.45g/ml = 4.662ml
"Gold"
100 grams of cube of gold × 1ml/ 19.28 g/ml = 5.187 g
Mas mataas ang gold kesa sa Platinum.
pa brainliest ty
8. How to tell if an aromatic compound is planar?
Answer:
Hope it helps
Explanation:
If the atoms arrange themselves around the central molecule so that they exist on a single two-dimensional plane, the molecule is planar. The molecule may otherwise form any of several three-dimensional shapes, including tetrahedrons, octahedrons or bipyramids.
9. planar rock fractures showing evidence of relative movement ?
Answer:
A fault is a fracture or break in the rock along which movement has taken place. The rupture and subsequent movement may be caused by tensional, compressional or shear forces.Explanation:
Hope it's helpMark me a brainlist please10. The planar surface where the focus is located is called
Answer:
epicenter
Explanation:
Epicenter is defined as the central point of something, or the point of the Earth's surface right above the focus of an earthquake.
Stay safe.
11. Which of the following best represents a planar state of stress?
Answer:
Thank you and sorry
[tex]\large{\orange{\mathbb{\underline{Hail Hydra}}}}[/tex]
[tex] \orange{ \rule{500pt}{555555pt}}[/tex]
Explanation:
salamat po ng maraming marami
Answer:
saan po yung following?
Explanation:
para may pagpipilian
12. what is FCC DANCE TROUP
Answer:
FCC means Federal Communications CommissionThe Federal Communications Commission regulates interstate and international communications by radio, television, wire, satellite, and cable in all 50 states, the District of Columbia and U.S. territories.Explanation:
i-Thank me later~─w─im Lazy...13. draw two dimensional trigonal Planar
Answer:
The central and surrounding atoms in a trigonal planar molecule lie on one plane (hence the term planar). This gives it more of a two-dimensional shape than three-dimensional. The bonds are spread equally around the plane, forming 120 degree bond angles.
Explanation:
^^
14. Find its density at 100˚C.
Answer:
The density of boiling water is 0.95865 grams/cm 3 .
Explanation:
❀⊱─━━━━━━⊱ ༻ ● ༺ ⊰━━━━━━─⊰❀
• ఌ︎☾︎__ kim__☽︎ ఌ︎ •
ⓒ︎Ⓞ︎Ⓡ︎Ⓡ︎Ⓔ︎Ⓒ︎Ⓣ︎Ⓛ︎Ⓨ︎
«« ❥︎ ----- StaySafe »»
15. What percent of the volume in an fcc structure is empty space?
Answer:
68% Hint: A simple or primitive cubic unit cell is the simplest repeating unit in a simple unit structure, and the empty space is the area in a cubic unit cell where no atom is present. We should first find out the effective number of atoms present.
Explanation:
I hope it's help
brainliest pls
16. a planar fracture between two rocks causing a fault
Answer:
FAULTExplanation:
Fault, in topography, a planar or delicately bended crack in the rocks of Earths hull, where compressional or tensional powers cause relative dislodging of the rocks on the contrary sides of the break. In topography, a fault is a planar break or irregularity in a volume of rock across which there has been critical dislodging because of rock-mass developments.
Ordinary faults occur in regions where the rocks are pulling separated so the rocky hull of a space can occupy more room. The rock on one side of the fault is dropped down comparative with the rock on the opposite side of the fault. Typical faults occur in regions where the rocks are pulling separated so the rocky hull of a space can occupy more room. The rock on one side of the fault is dropped down comparative with the rock on the opposite side of the fault. Ordinary faults won't make an overhanging rock edge.
Change faults The development along a strike slip fault is flat with the square of rock on one side of the fault moving one way and the square of rock along the opposite side of the fault moving the other way.
A fault in which the rock above the fault plane is displaced upward relative to the rock below the fault plane?: https://brainly.ph/question/10890866
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17. for an infinite planar charge of density ρs C/m2 the expression of the field intensity E above the plane is: Select one: a. E = ρs /2 b. None of these c. E = ρs /2ε d. E = 2.ρs /ε
Answer:
✏️ • B. None Of these________________________________
If you have any questions I'm always there to help. Hope it help, Stay safe & Study Hard.
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18. Austenite form of iron has FCC crystal lattice structure, whereas its alpha form has BCC crystal lattice structure. Assuming closest packed arrangement of iron atoms, what will be the ratio of density of Austenite to that of alpha iron?
ayan po sagot ko po...
19. •Shapes : positive, negative and planar issue
Answer:
SHAPES: POSITIVE, NEGATIVE & PLANAR ISSUES
A shape is defined as an enclosed area in two dimensions. By definition shapes are always implied and flat in nature. They can be created in many ways, the simplest by enclosing an area with an outline. They can also be made by surrounding an area with other shapes or the placement of different textures next to each other – for instance, the shape of an island surrounded by water. Because they are more complex than lines, shapes do much of the heavy lifting in arranging compositions. The abstract examples below give us an idea of how shapes are made.
Explanation:
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#CarryOnLearning#BrainliestAnswer
SHAPES: POSITIVE, NEGATIVE & PLANAR ISSUES
A shape is defined as an enclosed area in two dimensions. By definition shapes are always implied and flat in nature. They can be created in many ways, the simplest by enclosing an area with an outline. They can also be made by surrounding an area with other shapes or the placement of different textures next to each other – for instance, the shape of an island surrounded by water. Because they are more complex than lines, shapes do much of the heavy lifting in arranging compositions. The abstract examples below give us an idea of how shapes are made.
Shapes animate figure-ground relationships. We visually determine positive shapes (the figure) and negative shapes (the ground). One way to understand this is to open your hand and spread your fingers apart. Your hand is the positive shape, and the space around it becomes the negative shape.
A plane is defined as any surface area in space. In two-dimensional art, the picture plane is the flat surface an image is created upon; a piece of paper, stretched canvas, wood panel, etc. A shape’s orientation within the picture plane creates a visually implied plane, inferring direction and depth in relation to the viewer.
20. BCl3 : Trigonal Planar :: CO2
CO2 : Tetrahedral shape
21. This is not a prase, okay? Like i said, fcc kk u!
Answer:
ok
Explanation:
lol okay you arent even suppose to be in here tho
22. uuuuu ich d DDD FCC GB
Answer:
-----------------------------
a e I o u abasiakkuyesv23. 1. What is the mass of a billiard ball that has a density of 100 g/cm³ and a volume of 5 cm³ ? BONG Mass A Density x Volume WWW.REXBOOKSTORE.PH
Answer:
500g
Explanation:
Just multiply the density by the volume. 100x5
24. what is a planar polygon
Answer:
A polygon face is planar when: all of its vertices lie in a certain plane. For example, a triangle face is always planar, because its three points define a plane.
25. what is the density of population in 100 square meter size?
Answer:
Size is a saturated solution or an alternative that can be used for any other purposes only if the statement has been made by the sum of the article
26. What is the population density of 100 insects that live in the area of 100 square meters?
Answer:
1 insect per square meter
Answer: Population density is the average number of individuals in a population per unit of area or volume. For example, a population of 100 insects that live in an area of 100 square meters has a density of 1 insect per square meter.
27. calculate the density in g/L of nitrogen dioxide at 100°C and 5atm?
six months ago the same thing
Explanation:
1009288375×1992055482
28. If 100 butterflies are occupying an area of 250 sqm of garden, what is the population density?
ANSWER:
There are 0.4 butterflies per square miles.
EXPLAINATION:Population density is equal to [tex]\frac{Population}{Land area}[/tex]
Population density = [tex]\frac{100}{250}[/tex]
Population density = [tex]0.4[/tex]
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29. Silver is a metal commonly used in jewelry and photography. It crystallizes with a FCC unit cell 0.407 nm on an edge. What is the atomic radius of silver in cm? What is the volume of a single silver atom? What is the density of a single silver atom?
the atomic radius : r = 1.439 x 10⁻⁸ cm
the volume : 6.7419 x 10⁻²³ cm³
the density : 10.644 g/cm³
Further explanationThere are 3 main structures of the unit cell
1.Body-Centered Cubic (BCC), 2.Face Centered Cubic (FCC) 3. Hexagonal Close Packed (HCP).In the FCC, there are atoms on every corner and side
This form is found in metals such as Al, Cu, Ni, Fe.
The length of the face diagonal is equal to 4 times the atomic radius
[tex]\tt b=4r[/tex]
[tex]\tt a = r \sqrt{8}[/tex]
a = side length
b = diagonal of the side surface
r = atomic radius
Volume for unit cell :
[tex]\tt V=16r\sqrt{2}=a^3[/tex]
A number of atoms at an angle:
[tex]\tt 8\times \dfrac{1}{8}=1[/tex]
A number of atoms on the side of the surface
[tex]\tt 6\times \dfrac{1}{2}=3[/tex]
so that the total number of atoms = n = 4
Density:
[tex]\tt \rho=\dfrac{n.Ar}{V.N_o}[/tex]
Ar = atomic mass, g/mol
No = Avogadro number = 6.02.10²³
n = number of atoms
V = volume (cm³)
Known
a = 0.407 nm on an edge
a = 4.07.10⁻⁸ cm
the atomic radius of Silver(Ag)[tex]\tt a=r\sqrt{8}\\\\4.07\times 10^{-8}=r\sqrt{8}\\\\r=1.439\times 10^{-8}~cm[/tex]
the volume of a single silver atom[tex]\tt V=a^3\\\\V=(4.07\times 10^{-8})^3\\\\V=6.7419\times 10^{-23}~cm^3[/tex]
the density of a single silver atom[tex]\tt \rho=\dfrac{4\times 108~g/mol}{6.02\times 10^{23}\times 6.7419\times 10^{-23}}\\\\\rho=10.644~g/cm^3[/tex]
Learn morethe type of chemical bond
brainly.ph/question/74002
chemical reaction and chemical bonding
brainly.ph/question/2390656
chemical bonds
brainly.ph/question/114783
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30. example of chemical formula of trigonal planar
Answer:
Below are examples are a chemical formula that has a trigonal planar structure.
Boron Hydride
Boron trifluoride
Sulfur trioxide
Answer:
example of chemical formula of trigonal planar examples include:formaldehyde (CH2 O)sulfur trioxide (SO3)phosgene (COCl2)Explanation:
Trigonal planar geometries are also possible if the central atom of a compound shares double bonds with the other atoms. Even if the atom has a double bond, it still counts as one group.
